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25x-x^2=144
We move all terms to the left:
25x-x^2-(144)=0
We add all the numbers together, and all the variables
-1x^2+25x-144=0
a = -1; b = 25; c = -144;
Δ = b2-4ac
Δ = 252-4·(-1)·(-144)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-7}{2*-1}=\frac{-32}{-2} =+16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+7}{2*-1}=\frac{-18}{-2} =+9 $
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